(8) fаѕ irsg f | a catd la + b b a - dance b b + cc

The product of all values of t , for which the system of equations (a-t)x+b y+c z=0,b x+(c-t)y+a z=0,c x+a y+(b-t)z=0 has non-trivial solution, is |a-c-b-c b-a-b-a c| (b) |a b c b c a c a b| |a c bb a cc b a| (d) |a a+bb+c bb+cc+a cc+a a+b|

The product of all values of t , for which the system of equations (a-t)x+b y+c z=0,b x+(c-t)y+a z=0,c x+a y+(b-t)z=0 has non-trivial solution, is |a-c-b-c b-a-b-a c| (b) |a b c b c a c a b| |a c bb a cc b a| (d) |a a+bb+c bb+cc+a cc+a a+b|

Prove: |b+c a a b c+a b cc a+b|=4a b c

The figure shows the variation of photocurrent with anode potential for a photosensitve surface for three different radiations. Let l_a, l_b and l_c be the curves a, b and c, respectively (a) f_a = f_b and l_a != l_b (b) f_a = f_c and l_a = l_c (c ) f_a = f_b and l_a = l_b (d) f_b = f_c and l_b = l_c

The figure shows the variation of photocurrent with anode potential for a photosensitve surface for three different radiations. Let l_a, l_b and l_c be the curves a, b and c, respectively (a) f_a = f_b and l_a != l_b (b) f_a = f_c and l_a = l_c (c ) f_a = f_b and l_a = l_b (d) f_b = f_c and l_b = l_c

Prove that |b+c a a b c+a b cc a+b|=4a b c

Using the property of determinants and without expanding, prove that: |-a^2a b a c b a b^2b cc a c b-c^2|=4a^2b^2c^2

The value of determinant |a-bb-cc-a b-cc-a a-b c-a a-bb-c| is equal to- a b c b. 2a b c c. 0 d. none