`px^2-2sqrt5px+15=0`

If the quadratic equation px^(2)-2sqrt(5)px+15=0 has two equal roots,then find the value of p

If the quadratic equation px^(2)-2sqrt(5)+15=0 has two equal roots then find value of p.

If alpha, beta be the roots of px^(2)-qx +q=0 , then show that sqrt((alpha)/(beta)) +sqrt((beta)/(alpha)) - sqrt((g)/(p))=0 .

If one root of px^2 - 3x - 5 = 0 is 5/2, then the value of p is

The equation (10px^(2)-qx+r)(px^(2)-qx-5r)(5px^(2)-qx-r)=0(pqr!=0) has atleast

The roots of the equation x^(2)+px+q=0 are 1 and 2 .The roots of the equation qx^(2)-px+1=0 will be

If f(x)=(sqrt((1+px))-sqrt((1-px)))/x , -1lex =(2x+1)/(x-2) , 0lexle1 is continuous in the interval [-1,1] . Find P.