If `A = (-3, 4), B = (-1, -2), C = (5,6), D = (x,-4)` are vertices of a quadrilateral such that area of triangle ABD = 2 area of triangle ACD, then x =

If =(-3,4),B=(-1,-2),C=(5,6),D=(x,-4)A=(-3,4),B=(-1,-2),C=(5,6),D=(x,-4) are vertices of a quadrilateral such that area of triangle ABD=2 area of triangle ACD,then x=

If A=(-3,4), B=(-1,-2), C=(5,6) , D=(x,-4) are vertices of a quadrilateral such that triangle A B D=2 Delta A C D, then x=

If A=(-3, 4), B(-1, -2), C(5, 6), D(x, -4) are the vertices of a quadrilateral such that area of DeltaABD=2["Area of "DeltaACD] then x=

If A(-3,4),B(1,-2),C(5,6) and D(x,-4) are the vertices of a quadrilateral such that area of Delta ABC=Delta ACD then x=

If A(-5,\ 7),\ B(-4,\ -5),\ C(-1,\ -6)\ a n d\ D(4,\ 5) are the vertices of a quadrilateral, find the area of the quadrilateral ABCD.

If A(4,-6),B(3,-2) and C(5,2) are the vertices of $ABC, then verify the fact that a median of a triangle ABC divides it into two triangles of equal areas.

If A(x_1,y_1),B(x_2,y_2),C(x_3,y_3) are the vertices of the triangle then find area of triangle

The vertices of a triangle are A(4, 4), B(3, -2) and C(-3, 16). The area of the triangle is

If A(4,-6),B(3,-2) a n d C(5,2) are the vertices of A B C, and AD is median then verify the fact that a median of a triangle ABC divides it into two triangles of equal areas.