If a,b,c are the sides of a right triangle , where c is the hypotenuse. Prove that the radius r of the circle which touches the sides of the triangle is given by:`r=(a+b-c)/2`

If a, b, c are the side of a right triangle where c is the hypotenuse, prove that the radius of the circle which touches all the side of the triangle is given by r= (a+b-c)/2 .

If a, b, and c, are the sides of a right-angled triangle where C is the hypotenuse, prove that the radius r of the circle which touches the sides of the triangle is given by r=(a+b-c)/(2) units.

If a,b and c are sides of a ritht triangle where c is the hypotenuse, prove that the radius of the circle which touches the sides of the triangle is r = (a + b-c)/(2).

If a,b,c are the sides of a triangle and s=(a+b+c)/2 , prove that 8(s-a)(s-b)(s-c)leabc .

If a,b,c are the sides of a triangle and s=(a+b+c)/(2), then prove that 8(s-a)(s-b)(s-c)<=abc

86.a,b care the sides of a rightandangled triangle and a circle of radiusr touches the sides of the triangle.If cis the hypotenuse of the triangle,then the value of r is a+b+C(1)a+b+ca+b-c87. If one zero of the quadraticnolynomial d+ 15x+6 is reciprocal

Draw a right triangle whose hypotenuse is of length 4\ c m and one side is of length 2. 5\ c mdot

If Delta is the area of triangle whose sides are a,b,c then the area of the triangle with 2a,2b,2c as the sides is