" (ii) "sum_(k=1)^(n)[2^(k)+3^((k-1))]

sum_(k=1)^n k^3=

sum_(k=1)^(2n+1)(-1)^(k-1)k^(2)=

Find sum_(k=1)^(n)(1)/(k(k+1)) .

Fill in the blanks: (i) sum_(k=1)^(n)k=1+2+3+……………+n= ………… (ii) sum_(k=1)^(n)k^(2)=1^(2)+2^(2)+3^(2)+………………….+n^(2)= ……………….. (iii) sum_(k=1)^(n)k^(3)=1^(3)+2^(3)+3^(3)+…………..+n^(3)= …………………

Evaluate : sum_(k=1)^n (2^k+3^(k-1))

Evaluate : sum_(k=1)^n (2^k+3^(k-1))

sum_(k=1)^(2n+1) (-1)^(k-1) k^2 =

sum_(k =1)^(n) k(1 + 1/n)^(k -1) =