[" Mole fraction of glycerine(C "_(3)H_(5)(OH)_(3))" in a solution "],[" of "36g" of water and "46g" of glycerine is : "],[[" (1) "0.46," (2) "0.36],[" (3) "0.20," (4) "0.40]]

Mole fraction of C_(3)H_(5)(OH)_(3) in a solution of 36 g of water and 46 g of glycerine is :

Mole fraction of C_(3)H_(5)(OH)_(3) in a solution of 36 g of water and 46 g of glycerine is :

Mole fraction of C_(3)H_(5)(OH)_(3) in a solution of 36g of water and 46g of glycerine is:

Mole fraction of C_(3)H_(5)(OH)_(3) in a solution of 36g of water and 46g of glycerine is:

Calculate the mole fraction of C_(3)H_(5)(OH)_(3) in a solution of 36 g of water and 46 g of glycerine.

Mole fraction of glycerine C_3H_5(OH)_3 in solution containing 36 g of water and 46 g of glycerine is

Mole fraction of glycerine (mol,wt=92)" in a solution containing 36g of H_(2)O and 46g of glycerine is "

In a binary solution, the component present in smaller proportion is called solute while the one in excess is known as solvent. The solution containing 1 mole of the solute in 1L of solution is known as one molar solution while the solution in which 1 mole of solute is dissolved in 1 kg of the solvent is called one molal solution. The ratio of the no. of moles of a particular component to the total no. of moles in the solution is known as its mole fraciton The mole fraction of glycerine C_(3)H_(5)(OH)_(3) in a solution containing 36 g of water and 46 g of glycerine is :