[" 38."(10.3times10.3times10.3+1)/(10.3times10.3-10.3+1)(1)/(9times19times(1)/(8))geqslant0],[(12)/(8)=([" A) "9.3," (B) "10.3],[" (C) "11.3," (D) "12.3]]

(10.3 xx 10.3 xx 10.3 +1)/(10.3 xx 10.3 - 10.3 + 1) is equal to

Simplify: 10^(-1)times10^(2)times10^(-3)times10^(4)times10^(-5)times10^(6)

Simplify : e. 5 (1)/(3) xx (3)/(8) - (7)/(9) div 2 (1)/(10)

Simplify : ((1)/(12) + ((-3)/( 4)) + (7)/(8)) xx (3 (2)/(5) - (7)/(10) + ((-2)/( 15)) - 10 (1)/(30))

The following steps are involved in finding the value of 10 (1)/(3) xx 9(2)/(3) by using an appropriate indentity . Arrange them in sequential order . (A) (10)^(2) - ((1)/(3))^(2) = 100 - (1)/(9) (B) 10(1)/(3) xx 9(2)/(3) = (10 + (1)/(3)) (10 - (1)/(3)) (C) (10 + (1)/(3)) (10 - (1)/(3)) = (10)^(2) - ((1)/(3))^(2) [because (a + b) (a -b) = (a^(2) - b^(2))] (D) 100 - (1)/(9) = 99 + 1 - (1)/(9) = 99(8)/(9)

Is [(-10)xx1)]xx3=(-10)xx[(1xx3)] ?

(-5) xx (-2) xx (-10) xx (-8) xx (-3) = square

6. ^(*) The current in a metal wire of cross-sectional area 10^(-6)m^(2) is 1.6A .If the free electron density of the metal is 8times x^(2) x 10^(28)m^(-3) then the drift speed of electrons is (A) 1.25times10^(-3)ms^(-1) (B) 2times10^(-3)ms^(-1) (C) 1.25times10^(-4)ms^(-1) (D) 2times10^(-4)ms^(-1)