The last digit of `(3^P+2)`, where `P= 3^(4n+2)` is

The last digit of 3^(3^(4n))+1 , is

What is the last digit of 3^(3n)+1, where n is a natural number?

Which is the last digit of 1+2+3+……+ n if the last digit of 1 ^(3) + 2 ^(3) + ….. + n ^(3) is 1 ?

Which is the last digit of 1+2+3+……+ n if the last digit of 1 ^(3) + 2 ^(3) + ….. + n ^(3) is 1 ?

If p be any odd natural number, greater than 3 then which digit will never appear as the last digit in the product of (p^2 - 1)(p^2 + 1) is :

n whole numbers are randomly chosen and multiplied. Now, match the following lists. {:(" List I"," List II"),("a. The probability that the last digit is 1, 3, 7, or 9 is","p. "(8^(n)-4^(n))/(10^(n))),("b. The probability that the last digit is 2, 4, 6, 8 is ","q. "(5^(n) - 4^(n))/(10^(n))),("c. The probability that the last digit is 5 is","r. " (4^(n))/(10^(n))),("d. The probability that the last digit is zero is","s. "(10^(n) - 8^(n) - 5^(n) + 4^(n))/(10^(n))):}

n whole are randomly chosen and multiplied Column I, Column II The probability that the last digit is 1,3,7, or 9 is, p. (8^n-4^n)/(10^n) The probability that the last digit is 2,4,6, or 8 is, q. (5^n-4^n)/(10^n) The probability that the last digit is 5 is, r. (4^n)/(10^n) The probability that the last digit is zero is, s. (10^n-8^n-5^n+4^n)/(10^n)