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int(pi/4)^(3 pi/2)sqrt(1-cos2x)dx...

int_(pi/4)^(3 pi/2)sqrt(1-cos2x)dx

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int_(-pi//2)^(pi//2)sqrt(1-cos 2x)dx=

int_(-pi/2)^(pi/2) (sqrt(1+cos2x)/(sqrt2)) dx =

int_(-pi//2)^(pi//2) sqrt((1-cos2x)/2)dx =

The value of the integral int_(-pi/2)^(pi//2) sqrt((1+cos2x)/(2))dx is

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int_(0)^(pi//2) sqrt(1- cos 2x) dx

int_(0)^(pi//2) sqrt(1- cos 2x) dx

int_(0)^(pi//2) sqrt(1- cos 2x) dx

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Evaluate the following integral : int_pi^(3pi//2)sqrt(1-cos)\ 2x\ dx