In the arrangement shown in figure dielectric constant `K_1=2` and `K_2=3`. If the capacitance across `P` and `Q` are `C_1` and `C_2` respectively, then `C_1//C_2` wil be (the gaps shown are negligible)
`

Four identical plates 1, 2, 3 and 4 are placed parallel to each other at equal distance as shown in the figure. Plates 1 and 4 are joined together and the space between 2 and 3 is filled with a dielectric of dielectric constant k = 2. The capacitance of the system between 1 and 3 & 2 and 4 are C_1 and C_2 respectively . The ratio C_1/C_2 is

Four identical plates 1,2,3 and 4 are placed parallel to each other at equal distance as shown in the figure. Plates 1 and 4 are joined together and the space between 2 and 3 is filled with a dielectric of dielectric constant k =2 . The capacitance of the system between 1 and 3 and 2 &4 are C_(1) and C_(2) respectively. The ratio (C_(1))/(C_(2)) is-

The capacitance of a capacitor, filled with two dielectrics of same dimensions but of dielectric constants K_1 and K_2 respectively as shown will be -

In the figure shown P_(2) and P_(2) are two conducting plates having charges of equal magnitude and opposite sign. Two dielectrics of dielectric constant K_(1) and K_(2) fill the space between the plates as shown in the figure. The ratio of electrical energy in 1^("st") dielectric to that in the 2^(nd) dielectric is :

In the arrangement shown, the battery is disconnected and a dielectric slab of dielectric constant K is insereted between the plates of capacitor with capacitance C, so as to completely fill the space. What is the final potential differnece across capacitor with capacitance 2C ?

A parallel plate capacitor of plate area A and separation d filled with three dielectric materials as show in figure. The dielectric constants are K_1 , K_2 and K_3 respectively. The capacitance across AB will be :

Consider a parallel plate capacitor. When half of the space between the plates is filled with some dielectric material of dielectric constant K as Shown in Fig. (1) below, the capacitance is C_(1) . However , if the same dielectric material fills half the space as shown as shown in Fig. (2), the capacitance is C_(2) . Therefore, the ratio C_(1):C_(2) is

Consider a parallel plate capacitor. When half of the space between the plates is filled with some dielectric material of dielectric constant K as Shown in Fig. (1) below, the capacitance is C_(1) . However , if the same dielectric material fills half the space as shown as shown in Fig. (2), the capacitance is C_(2) . Therefore, the ratio C_(1):C_(2) is