Home
Class 9
MATHS
If the bisectors of the opposite angles ...

If the bisectors of the opposite angles `/_Pa n d/_R` of a cyclic quadrilateral `P Q R S` intersect the corresponding cicle at `Aa n dB` respectively, then `A B` is a diameter of the circle.

Promotional Banner

Similar Questions

Explore conceptually related problems

If the bisectors of the opposite angles /_P and /_R of a cyclic quadrilateral PQRS intersect the corresponding cicle at A and B respectively,then AB is a diameter of the circle.

If the bisectors of the opposite angles /_Aa n d/_B of a cyclic quadrilateral A B C D intersect the corresponding cicle at P an d Q respectively, then P Q is a diameter of the circle.

If the bisectors of the opposite angle /_P and /_Rof a Cyclic quadrilateral PQRS intersect the cooresponding circle at A and B respectively; then AB is a diameter of the circle.

If bisectors of opposite angles of a cyclic quadrilateral ABCD intersect the circle, circumscribing it at the points P and Q, prove that PQ is a diameter of the circle.

If bisectors of opposite angles of a cyclic quadrilateral ABCD intersect the circle, circumscribing it at the points P and Q, prove that PQ is a diameter of the circle.

If bisectors of opposiste angles of a cyclic quadrilateral ABCD intersect the circle, circumscribing it at the points P and Q, prove that PQ is a diameter of the circle.

In a cyclic quadrilateral ABCD, the bisectors of opposite angles A and C meet the circle at Pand Q respectively. Prove that PQ is a diameter of the circle.

ABCD is a cyclic quadrilateral. The bisectors of angleDAB and angleBCD intersect the circle at the points X and Y respectively. Prove that XY is a diameter of the circle.

Prove that the internal bisector of any angle of a cyclic quadrilateral and the external bisector of its opposite angle intersect each other on the circumference of the circle.

The bisectors of the angles formed by producing the opposite sides of a cyclic quadrilateral (provided that they are not parallel) intersect at right angle.