A particle executes `SHM` on a line `8` cm long. Its `K.E.` and `P.E.` will be equal when its distance from the mean position is :-

A particle executes SHM on a line 8 cm long . Its KE and PE will be equal when its distance from the mean position is

A particle executes SHM on a line 8 cm long . Its KE and PE will be equal when its distance from the mean position is

At what distance from mean position is K.E equal to P.E?

A particle executing SHM has amplitude of 4cm, and its acceleration at a distance of 1cm from the mean position is 3cm^(-2) . What will its velocity be when it is at a distance of 2 cm from its mean position?

The kinetic energy of paritcle executing SHm will be equal to ((1)/(8))^(th) of its potential energy when its displacement from the mean position is (Where A is the amplitude) :