`Ifintxe^xcosx dx=a e^x(b(1-x)sinx+c xcosx)+d ,t h e n` `a=1,b=1,c=-1` `a=1/2,b=-,c=1` `a=1,b=-1,c=1` `a=1/2, b=1,c=-1`

Ifintxe^xcosx dx=a e^x(b(1-x)sinx+c xcosx)+d ,t h e n (a) a=1,b=1,c=-1 (b) a=1/2,b=-,c=1 (c) a=1,b=-1,c=1 (d) a=1/2, b=1,c=-1

Ifintxe^xcosx dx=a e^x(b(1-x)sinx+c xcosx)+d ,t h e n (a) a=1,b=1,c=-1 (b) a=1/2,b=-,c=1 (c) a=1,b=-1,c=1 (d) a=1/2, b=1,c=-1

If int xe^(x)cos xdx=ae^(x)(b(1-x)sin x+cx cos x)+d, the a=1,b=1,c=-1a=(1)/(2),b=-,c=1a=1,b=-1,c=1a=(1)/(2),b=1,c=-1

If intx^(2)*e^(-2x)dx=e^(-2x)(ax^(2)+bx+c)+d , then a) a=1,b=1,c=1/2 b) a=1,b=-1,c=-1/2 c) a=1,b=-1,c=-1/2 d)None of these

If int(xln(x+sqrt(1+x^2)))/(sqrt(1+x^2))dx =asqrt(1+x^2)ln(x+sqrt(1+x^2))+b x+c , then (A) a=1,b =-1 (B) a=1,b=1 (C) a=-1, b=1 (D) a=-1, b=-1

If int(xln(x+sqrt(1+x^2)))/(sqrt(1+x^2))dx =asqrt(1+x^2)ln(x+sqrt(1+x^2))+b x+c , then (A) a=1,b =-1 (B) a=1,b=1 (C) a=-1, b=1 (D) a=-1, b=-1

If f(x)=f(x)={(sin(a+1)x+sinx)/(x), ,x<0,c \ at x=0, (sqrt(x+b x^2)-sqrt(x))/(b xsqrt(x)),xgeq0,f(x) is continuous at x=0,t h e n (a). a=-3/2,b=0,c=1/2 (b) a=-3/2,b=1,c=-1/2 (c) a=-3/2,b in R-[0],c=1/2 (d) none of these

If int(cos4x+1)/(cotx-tanx)dx = Acos4x+B ,t h e n (a) A=-1/8 (b) B=1/2 (c) A=-1/4 (d) None of this

int(ln(x+sqrt(1+x^(2))))/(sqrt(1+x^(2)))dx=a sqrt(1+x^(2))ln(x+sqrt(1+x^(2)))+bx+c, then (A)a=1,b=-1(B)a=1,b=1(C)a=-1,b=1 (D) a=-1,b=-1

If the line y=x touches the curve y=x^2+b x+c at a point (1,\ 1) then b=1,\ c=2 (b) b=-1,\ c=1 (c) b=2,\ c=1 (d) b=-2,\ c=1