A circuit contains two inductors of self-inductance `L_(1)` and `L_(2)` in series (Fig) If `M` is the mutual inductence, then the effective inductance of the circuit shows will be

The inductors of self inductance L_(1) and L_(2) are put in series .

The inductors of self inductance L_(1) and L_(2) are put in series .

Self inductance || L-R Circuit

Direction. In the follwing questions, a statement of assertion is followed by a statement of reason. While answering a question, you are required to choose the correct are out of the given four responses and mark it as (A). If both assertion and reason are true and reason is the correct explanation of the assertion, (B) if both assertion and reason are true but reason is not correct explanation of the assertion. (C) if asssertion is true, but reason if false, (D) if both assertion and reason are false Assertion : A circuit contains two inductors in series with self-inductances L_1 and L_2 and mutual inductance M. The equivalent inductance in the circuit is given by L = L_1 + L_2 + 2 M Reason : The given relation is incorrect, as at a time the two inductors can either possess self-inductance or a mutual inductance.

Mutual inductance of two coils depends on their self inductance L_(1) and L_(2) as :

Mutual inductance of two coils depends on their self inductance L_(1) and L_(2) as :

L-R circuit and mutual inductance

Self inductance| Inductors and RL circuits