The first and last terms of an AP are `a` and `l` respectively. If `S` be the sum of terms then show that the common difference is `(l^2-a^2)/(2S-(a+l))`

The first and last terms of an A.P. are a and l respectively. If S be the sum of the terms then show that the common difference is (l^(2) - a^(2))/(2S - (l+a)) .

The first and last term of an A.P. are a and l respectively. If S be the sum of all the terms of the A.P., them the common difference is

The first and last term of an A.P. are a and l respectively. If S be the sum of all the terms of the A.P., them the common difference is

The first and last elements of an A.P are a and l respectively. If S is the sum of all terms of the A.P, then the common difference is

The first and last term of an A.P. are a and l respectively. If S is the sum of all the terms of the A.P. and the common difference is given by (l^2-a^2)/(k-(l+a)) , then k= (a) S (b) 2S (c) 3S (d) none of these

The first and last term of an A.P. are a and l respectively. If S is the sum of all the terms of the A.P. and the common difference is given by (l^2-a^2)/(k-(l+a)) , then k= (a) S (b) 2S (c) 3S (d) none of these

The first and the last term of an AP are 7 and 49 respectively. If the sum of all its terms is 420, find the common difference.

The first and last term of an A.P.are a and l respectively.If S is the sum of all the terms of the A.P.and the common difference is given by (l^(2)-a^(2))/(k-(l+a)), then k=(a)S(b)2S(c)3S(d) none of these