if `1,omega,omega^2` root of the unity then The roots of the equation `(x-1)^3 + 8 = 0` are

If 1,omega,omega^(2) are the cube roots of unity, then the roots of the equation (x-1)^(3)+8=0 are

If 1,omega,omega^(2) are the cube roots of unity, then the roots of the equation (x-1)^(3)+8=0 are

If the cube roots of unity are 1 , omega , omega^(2) , then find the roots of the equation ( x - 1)^(3) + 8 = 0 .

If the cube root of unity are 1,omega,omega^(2) , then the roots of the equation (x-1)^(3)+8=0 are :

If the cube roots of unity are 1,omega,omega^2, then the roots of the equation (x-1)^3+8=0 are

If the cube roots of unity are 1,omega,omega^(2) then the roots of the equation (x-1)^(3)+8=0 are

If the cube roots of unity are 1, omega , (omega)^2 , then the roots of the equation (x-2)^3+27 = 0 are

If omegane1 is a cube root of unity, show that the roots of the equation (z-1)^(3)+8=0 are -1,1-2omega,1-2omega^(2) .

If the cube roots of unity are 1, omega, omega^(2) then the roots of the equation (x-1)^(3)+8=0 , are