If `r sin theta = sqrt3, r + 4 sin theta = 2(sqrt3 + 1)`,and `0 <= theta <= 2pi`, then `theta =`

Sin theta = sqrt3 / 2

If r sin theta = sqrt(3), r + 4 sin theta = 2(sqrt(3)+1), 0 le theta le 2pi , then theta =

If r sin theta=sqrt(3),r+4sin theta=2(sqrt(3)+1), and 0<=theta<=2 pi, then theta=

Find all values of theta lying between 0 and 2 pi satisfying the equation r sin theta = sqrt 3 and r + 4 sin theta =2(sqrt 3+1)

Find all values of theta lying between 0 and 2 pi satisfying the equation r sin theta = sqrt 3 and r + 4 sin theta =2(sqrt 3+1)

Find all values of theta lying between 0 and 2 pi satisfying the equation r sin theta = sqrt 3 and r + 4 sin theta =2(sqrt 3+1)

Given rsintheta = sqrt(3), r+4sin theta = 2(sqrt(3)+1) where 0 le theta le 2pi Value of r will be-

Given rsintheta = sqrt(3), r+4sin theta = 2(sqrt(3)+1) where 0 le theta le 2pi Value of theta will be-

If r cos theta = 3 and r sin theta = sqrt3 , then find the value of r and theta .