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[" A."2" .B."4],[" 12."sqrt(3)csc20^(@)-...

[" A."2" .B."4],[" 12."sqrt(3)csc20^(@)-sec20^(@)" frufferen "(1)/(n)" arlar "(1)/(e)" : "],[[" A."2," B."2sin20%],[" C."4," D."4sin20^(@)sin4]]

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Q.sqrt(3)cos ec20^(@)-sec20^(@)=

sqrt(3)cos sec20^(0)-sec20^(@)

sqrt3"cosec"20^(@) - sec20^@ =

sqrt3" cosec "20^(@)-sec20^(@)=

sqrt(3)" cosec "20^(@)-sec20^(2)=?

sqrt2 "cosec"20^@ sec20^@ =

Show that sqrt(3)cos ec20^(@)-sec20^(@)=4

Show that sqrt(3)cos ec20^(@)-sec20^(@)=4

sqrt(2)* " cosec " 20^(@) sec 20^(@)=