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-8 m-2=17...

`-8 m-2=17`

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If x is real, find the minimum value of x^(2)-8x+ 17

Find the matrix A if A^2=[[17,8,],[8,17,]].

Solve the following pair of linear equations by substitution method : 2x+y=17 , 17x-11y=8 .

Through point P(-1,4) , two perpendicular lines are drawn which intersect x-axis at Q and R. find the locus of incentre of Delta PQR . a. x^2+y^2+2x-8y-17=0 b. x^2-y^2 +2x-8y+17=0 c. x^2+y^2-2x-8y-17=0 d. x^2-y^2+8x-2y-17=0

If x is real, the maximum value of x^2 -8x + 17 is

Simplify : 16-[11-{8-:(17+3xx2-19)}]

the minimum value of x^2 - 8x +17 , AA x in R is

The equation e^(x-8)+2x-17=0 has :

The equation e^(x-8)+2x-17=0 has :