A concave lens of glass, refractive index 1.5 has both surfaces of same radius of curvature R. On immersion in a medium of refractive index 1.75, it will behave as a

A convax lens of glass ,refractive index 1.5 ,has both surfaces of same radius of curvature R. On immersion in a medium of refractive index 1.75 ,it wuill behaves as a (A)convergent lens of focal length 3.5R (B)convergent lens of focal length 3.0R (C)divergent lens of focal length 3.5R (D)divergent lens of focal length 3.0R

The two surfaces of a concave lens, made of glass of refractive index 1.5 have the same radii of curvature R. It is now immersed in a medium of refractive index 1.75, then the lens

A convex lens made up of glass of refractive index 1.5 is dippedin turn (i) in a medium of refractive index 1.65 (ii) in a medium of refractive index 1.33 Then Will it behave as converging or diverging lens in the two cases ?

A convex lens made up of glass of refractive index 1.5 is dippedin turn (i) in a medium of refractive index 1.65 (ii) in a medium of refractive index 1.33 (a) Will it behave as converging or diverging lens in the two cases ? (b) How will its focal length changes in the two media ?

A convex lens made up of glass of refractive index 1.5 is dippedin turn (i) in a medium of refractive index 1.65 (ii) in a medium of refractive index 1.33 (a) Will it behave as converging or diverging lens in the two cases ? (b) How will its focal length changes in the two media ?