For a projectile, the ratio of maximum height reached to the square of flight time is `(g = 10 ms^(-2))`

" For a projectile the ratio of the square of the time of flight to its maximum height is "

For a projectile the ratio of the square of the time of flight to its maximum height is (A) 5:4 (B) 5:2 (C) 4:5 (D) 10:1

A body is projected with an angle theta .The maximum height reached is h .If the time of flight is 4 sec and g=10m//s^(2) ,then the value of h is

A body is projected with an angle theta . The maximum height reached is h. If the time of flight is 4 sec and g=10m//s^2 , then the value of h is

A stone is projected in air. Its time of flight is 3s and range is 150m. Maximum height reached by the stone is (Take, g = 10 ms^(-2))