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[" The horizontal component of the earth's "],[" magnetic field at a place is "3times10^(-4)T" and the "],[" dip is "theta=tan^(-1)(4/3)" .A metal rod of length "0.25m],[" placed in the north-south position is moved at "],[" a constant speed of "10m/s" towards the east.The "],[" e.m.finduced in the rod will be: "],[[" 1) zero ",2" ) "1mV," 3) "5mV," 4) "10mV]]

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