`sqrt(x+5)+sqrt(x-20)=7`

sqrt(x+5)+sqrt(20-x)=7

sqrt(x+4)+sqrt(x+20)=2sqrt(x+11)

Using properties of proportion, solve for x : (i) (sqrt(x + 5) + sqrt(x - 16))/ (sqrt(x + 5) - sqrt(x - 16)) = (7)/(3) (ii) (sqrt(x + 1) + sqrt(x - 1))/ (sqrt(x + 1) - sqrt(x - 1)) = (4x -1)/(2) . (iii) (3x + sqrt(9x^(2) -5))/(3x - sqrt(9x^(2) -5)) = 5 .

If "log"_(7){"log"_(5)(sqrt(x+5) + sqrt(x))}=0 then x =

Find harmonic mean of equation (2sqrt(5)+sqrt(33))x^(2)-(3+sqrt(5))x+6+sqrt(20)=0

sqrt(x)-sqrt(1-x)=(1)/(5) and sqrt(x)+sqrt(1-x)=(7a)/(5) then the value of a is :

What is the value of x in the following expression? log_(7)log_(5)[sqrt((x+5))+sqrt(x)]=0

Find the value of sqrt(-5x^8) - sqrt(-20x^8) + sqrt(-45x^8) , where x is a positive real number.