For the reaction `2A(g)+B(g)hArr C(g)+D(g), K_c=10^(12)`.if initially 4,2,6,2 moles of A,B,C,D respectively are taken in a 1 litre vessel, then the equilibrium concentration of A is :

At a certain temperature the equilibrium constant K_(c) is 0.25 for the reaction A_(2)(g)+B_(2)(g) hArr C_(2)(g)+D_(2)(g) If we take 1 mole of each of the four gases in a 10 litre container, what would be equlibrium concentration of A_(2)(g) ?

At a certain temperature the equilibrium constant K_c is 0.25 for the reaction A_(2(g))+B_(2(g)) harr C_(2(g))+D_(2(g)) If we take 1 mole of each of the four gases in a 10 litre container, what would be equilibrium concentration of A_(2(g)) ?

At a certain temperature the equilibrium constant K_(c) is 0.25 for the reaction A_(2)(g)+B_(2)(g)hArrC_(2)(g)+D_(2)(g) If we take 1 mole of each of the four gases in a 10 litre container ,what would be equilibrium concentration of A_(2) (g)?

At a certain temperature the equilibrium constant K_(c) is 0.25 for the reaction A_(2)(g)+B_(2)(g)hArrC_(2)(g)+D_(2)(g) If we take 1 mole of each of the four gases in a 10 litre container ,what would be equilibrium concentration of A_(2) (g)?

At a certain temperature the equilibrium constant K_(c) is 0.25 for the reaction A_(2)(g)+B_(2)(g)hArrC_(2)(g)+D_(2)(g) If we take 1 mole of each of the four gases in a 10 litre container ,what would be equilibrium concentration of A_(2) (g)?

In the reaction X(g)+Y(g)hArr2Z(g),2 mole of X,1 mole of Y and 1 mole of Z are placed in a 10 litre vessel and allowed to reach equilibrium .If final concentration of Z is 0.2 M , then K_(c) for the given reaction is :

In the reaction X(g)+Y(g)hArr2Z(g),2 mole of X,1 mole of Y and 1 mole of Z are placed in a 10 litre vessel and allowed to reach equilibrium .If final concentration of Z is 0.2 M , then K_(c) for the given reaction is :

In the reaction X(g)+Y(g)hArr2Z(g),2 mole of X,1 mole of Y and 1 mole of Z are placed in a 10 litre vessel and allowed to reach equilibrium .If final concentration of Z is 0.2 M , then K_(c) for the given reaction is :