(xi)((1)/(2)x^((1)/(3))+x^(-(1)/(3)))^(8)

(ii) [(1)/(2)x^(1/3)+x^(-1/5)]^(8)

(2^((3x-1)/(x-1)))^((1)/(3))<8^((x-3)/(3x-7))

(x+1)/(2)+(y+1)/(3)=9,(x-1)/(3)+(y+1)/(2)=8 then x=………

(x+1)/(2)+(y-1)/(3)=8;(x-1)/(3)+(y+1)/(2)=9

[int((x+x^(3))^(1/3))/(x^(4))dx" is equal to "],[[" (1) "(3)/(8)((1)/(x^(2))-1)^(4/3)+c," (2) "-(3)/(8)[(1+(1)/(x^(2)))^(4/3)]+c],[" (3) "(1)/(8)(1+(1)/(x^(2)))^(4/3)+c," (4) "(1)/(8)((1)/(x^(2))-1)^(4/3)+c]]

" If (3x^(3)-8x^(2)+10)/((x-1)^(4))=(3)/(x-1)+(1)/((x-1)^(2))-(7)/((x-1)^(3))+(k)/((x-1)^(2)) then "k=

If x is so small that x^(3) and higher powers of x may be neglectd,then ((1+x)^(3/2)-(1+(1)/(2)x)^(3))/((1-x)^(1/2)) may be approximated as 3x+(3)/(8)x^(2) b.1-(3)/(8)x^(2) c.(x)/(2)-(3)/(x)x^(2) d.-(3)/(8)x^(2)

int_1^8((x^(1/3)-1)(2-x^(2/3)))/x^(1/3)

If the graph of the function f(x)=(a^(x)-1)/(x^(n)(a^(x)+1)) is symmetrical about the y-a xi s,then n equals 2 (b) (2)/(3)(c)(1)/(4) (d) (1)/(3)