If the distance between the foci of a hyperbola is `16` and its eccentricity is `sqrt(2)` , then obtain its equation.

If the distance between the foci of a hyperbola is 16 and its eccentricity is sqrt(2) , then obtain the equation of the hyperbola.

The distance between the focii of a hyperbola is 16 and its eccentricity is sqrt2 . Its equation is

The distance between the foci of a hyperbola is 16 and its eccentricity is sqrt2 . Its equation is :

The distance between the foci of a hyperbola is 16 and its eccentricity is sqrt(2) then equation of the hyperbola is

The distance between the foci of a hyperbola is 16 and its eccentricity is sqrt(2) then equation of the hyperbola is

The distance between the foci of a hyperbola is 16 and its eccentricity is sqrt(2) then equation of the hyperbola is a. x^2+y^2=32 b. x^2-y^2=16 c. x^2+y^2=16 d. x^2-y^2=32

The distance between foci of a hyperbola is 16 and its eccentricity is sqrt2 , then the equation of hyperbola is

The distance between the foci of a hyperbola is 16 and its eccentricity is sqrt(2) then equation of the hyperbola is x^(2)+y^(2)=32b.x^(2)-y^(2)=16c*x^(2)+y^(2)=16dx^(2)-y^(2)=32

The distance between the foci of a hyperbola is 16 and e = sqrt2 . Its equation is