`(x^a/x^b)^(a+b-c)*(x^b/x^c)^(b+c-a)*(x^c/x^a)^(c+a-b)=?` a. `1` b. `x^(abc)` c. `x^(ab+bc+ca)` d. `x^(a+b+c)`

(x^a/x^b)^(a+b).(x^b/x^c)^(b+c).(x^c/x^a)^(c+a)

((x^(a))/(x^(b)))^(a+b)*((x^(b))/(x^(c)))^(b+c)*((x^(c))/(x^(a)))^(c+a)=? a.0 b.x^(abc) c.x^(a+b+c)d.1=? a.0

((x^(a))/(x^(b)))^(1/ab)*((x^(b))/(x^(c)))^(1/bc)*((x^(c))/(x^(a)))^(1/ca)=? a.11 b.x^(1/abc) c.x^(1/(ab+bc+ca)) d.None of these

Prove that :((x^(a))/(x^(b)))^(a+b-c)((x^(b))/(x^(c)))^(b+c-a)((x^(c))/(x^(a)))^(c+a-b)=1

(x^(b)/(x^(c)))^(a)xx(x^(c)/(x^(a)))^(b)xx(x^(a)/(x^(b)))^(c)=1

Simplify: x^(b-c)a. x^(c-a)b. x^(a-b)c

The value of (x^a/x^b)^(a^2+ab+b^2)(x^b/x^c)^(b^2+bc+c^2)(x^c/x^a)^(c^2+ca+a^2)

(x^(b)/x^(c ))^(1/(bc))xx(x^(c )/x^(a))^(1/(ca))xx(x^(a)/x^(b))^(1/(ab))