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if nPr=720 nCr,the value of r and the n...

if `nP_r=720 nC_r`,the value of `r` and the no. of six digit no. all digits which are odd is ,and if `12P_r=11P_6+2*11P_5 , r=?` and if `35C_(n+7)=35C_(4n-2)` then `n` is equals to:

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