If `R` is the horizontal range for `theta` inclination and `h` is the maximum height reached by the projectile, Then maximum range is

If R is the horizontal range for theta inclination and h is the maximum height reached by the projectile, show that the maximum ragne is given by (R^(2))/(8h) + 2h .

If R is the horizontal range for theta inclination and h is the maximum height reached by the projectile, show that the maximum ragne is given by (R^(2))/(8h) + 2h .

The horizontal range is four times the maximum height attained by a projectile. The angle of projection is

The horizontal range is four times the maximum height attained by a projectile . The angle of projection is

The horizontal range (R ) of a projectile becomes (R + 2 H) from R due to a wind in horizontal direction. Here H is the maximum height reached by the projectile. What constant horizontal acceleration is imparted by the wind ?

The horizontal range (R ) of a projectile becomes (R + 2 H) from R due to a wind in horizontal direction. Here H is the maximum height reached by the projectile. What constant horizontal acceleration is imparted by the wind ?

Show that maximum horizontal range is 4 times the maximum height attained by the projectile.

Prove that the maximum horizontal range is four times the maximum height attained by the projectile, when fired at an inclination so as to have maximum horizontal range.

Prove that the maximum horizontal range is four times the maximum height attained by the projectile, when fired at an inclination so as to have maximum horizontal range.