A pendulum clock has an iron pendulum 1 m long `(alpha_("iron")=10^(-5) //^(@)C)` . If the temperature rises by `10^(@)C`, the clock

A clock with an iron pendulum keeps correct time at 15^(@)C . If the room temperature rises to 20^(@)C , the error in sconds per day will be (coefficient of linear expansion for iron is 0.000012//^(@)C)

A clock with an iron pendulum keeps correct time at 15^(@)C . If th room temperature rises to 20^(@)C , the error in second per day will be (coefficient of linear expansion of iron is 0.000012^(@)C )

A pendulum clock keeps correct time at 20^(@)C and coefficient of linear expansion of pendulum is 12xx10^(-6)//.^(@)C . If the room temperature increases to 40^(@)C , how many seconds the clock lose or gain per day?

A pendulum clock with a pendulum made of Invar (a = 0.7 xx10^(-6)//""^@C) has a period of 0.5 and is accurate at 25^@C . If the clock is used in a country where the temperature average 35^@C , What correction is necessary at the end of a month (30 days) to the time given by the clock?

Calculate the percentage increase in the moment of inertia of a ring of iron. Given that alpha_("iron")=11xx10^(-6).^(@)C^(-1) and rise in temperature is 20^(@)C

A second's pendulum clock havig steeel wire is calibrated at 20^(@) C. When temperature is increased to 30^(@) C, then calculate how much time does the clock [alpha_(Steel) = 1.2xx10^(-6^(@))C^(-1)

Two pendulum clocks, one having an iron pendulum and the other having a brass pendulu, are keeping correct time at 5^(@)C . How much per day will they differ at 25^(@)C ? alpha_("iron")=12xx10^(-5).^(@)C^(-1), alpha_("brass")=18.7xx10^(-6).^(@)C^(-1)

A pendulum clock is 5 sec. Slow at a temperature 30^(@)C and 10 sec. fast at a temperature of 15^(@)C , At what temperature does it give the correct time-