`1 g` of hydrogen is converted into `0.993 g` of helium in a thermonuclear reaction. The energy released is.

If 1gm hydrogen is converted into "0.993gm" of helium in a thermonuclear Reaction,the energy released in the reaction is 9 lambda times10^(10)J .Then the value of lambda is

In a thermo-nuclear reaction 1.00xx10^(-3)kg hydrogen is converted into 0.993xx10^(-3)kg helium. (a) Calculate the energy released m joule. (b) If the efficiency of the generator be 5%, calculation the energy in kilowatt hours.

In nuclear fusion, One gram hydrogen is converted into 0.993 gm . If the efficiency of the generator be 5% , then energy obtained in KWH is

In a thermo nuclear reaction 10^(-3)Kg of hydrogen is converted into 0.99xx10^(-3)Kg of helium. If the efficiency of the generator is 50% , the electrical energy generated in KWH is

In any nuclear reaction 1/1000 part of the mass of a particular substance is converted into energy. If 1 g of that substance takes part in a nuclear reaction then determine the energy evolved in kilowatt-hour

The Delta_(eg)H^(ɵ) of Br is 3.4 eV . How much energy in kcal is released when 0.8 g of Br (g) is completely converted to Br^(ɵ) (g) ions. (1 eV = 23.06 kcal mol^(1-)) b. The energy released when 10^(7) atoms of I (g) is converted to I^(ɵ) (g) ions, is 5 xx 10^(-13) J . Calculate Delta_(eg)H^(ɵ) of I (g) in (i) eV "atom"^(-1) and (ii) kJ mol^(-1) .