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[" If the molar conductance of "Ca(2+)" and "],[Cl^(T)" at infinite dilution are respectively "],[118.88times10^(-4)m^(2)" mho mol- "^((-1))" and "],[77.33times10^((-4))m^(2)" mho mol- "(-1)" then that of "],[CaCl_(2)" is "(inm^(2)mhomol^((-1)))]

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If the molar conductance values of Ca^(2+) and Cl^(-) at infinite dilution are respectively 118.88xx10^(-4) m^(2) mho mol^(-1) and 77.33xx10^(-4) m^(2) mho mol^(-1) then that of CaCl_(2) is : (in m^(2) mho mol^(-1) )

If the molar conductivity values of Ca^(2+) and Cl^(-) at infinite dilution are, respectively, 118.88 xx 10^(-4) and 77.33 xx 10^(-4) S m^(2) mol^(-1) , then that of CaCl_(2) is ( Sm^(2) mol^(-1) )

At 25^(@)C , if the molar ionic conductance of Ca^(2+) and Cl^(-) ions in an infinitely dilute soltuion of CaCl_(2) are "119 ohm"^(-1)."cm"^(2)."mol"^(-1) and "76.5 ohm"^(-1)."cm"^(2)."mol"^(-1) , respectively, then for the solution -

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The molar conductivities of H^(+) and HCOO^(-) ions at infinite dilution are 34.7 and 5.4 mSm^(2) " mol"^(-1) respectively. The molar conductivity of 0.25 M HCOOH is 4.0 mSm^(2) mol^(-1) . Then pK_(a) of formic acid is