`int(cosx-sinx)/(1+sin2x)`dx

If int(cosx-sinx)/(8-sin2x)dx=(1)/(p)log[(3+sinx+cosx)/(3-sinx-cosx)]+c , then p= . . . .

int(cosx+sinx)/sqrt(sin2x)dx= (A) sin^-1(cosx+sinx) (B) sin^-1(sinx-cosx) (C) cos^-1(cosx+sinx) (D) none of these

int(cosx-sinx)/sqrt(8-sin2x)dx=Asin^(-1)((sinx+cosx)/B), (A,B)=

inte^x((cosx-sinx)/(sin^2x))dx=

int(cosx-sinx)/(1+2sin x cosx)dx is equal to

int(cosx+sinx)/(sqrt(1+sin2x))dx,x in[-(pi)/(4),(3pi)/(4)]

Evaluate the following integrals: int (cosx-sinx)/(sqrt(1-sin2x)) dx, 0ltxltpi/4

int(cosx-sinx)/(( sin x+ cos x)^(2))dx

Evaluate int(cosx-sinx)/(cosx+sinx)(2+2sin2x)dx

Evaluate: int(cosx-sinx)/(cosx+sinx)(2+2sin2x)dx