Home
Class 12
MATHS
the continued product 2.6.10.14.... to n...

the continued product 2.6.10.14.... to `n` factors is equal to `^2n p_n` (b) `^2n C_n` `(n+1)(n+2)(n+3)(n+n)` `2^ndot(1. 3. 5 ..2 n-1)`

Promotional Banner

Similar Questions

Explore conceptually related problems

the continued product 2.6.10.14... to n factors is equal to 2np_(n)(b)^(2n)C_(n)(n+1)(n+2)(n+3)...(n+n)2^(n)*(1.3.5......2n-1)

Show that 2.6.10.14.. To n factors =(n+1)(n+2)(n+3) … to n factors.

Prove that ^n C_0 ^(2n)C_n- ^n C_1 ^(2n-2)C_n+ ^n C_2^(2n-4)C_n-=2^ndot

Prove that ((2n+1)!)/(n !)=2^n{1. 3. 5 .........(2n-1)(2n+1)}

Prove that .^n C_0 . ^(2n) C_n- ^n C_1 . ^(2n-2)C_n+^n C_2 . ^(2n-4)C_n-=2^ndot

Prove that: ((2n)!)/(n !)={1. 3. 5 (2n-1)}2^ndot

Prove that: ((2n)!)/(n !)={1. 3. 5 (2n-1)}2^ndot

Prove that: ((2n)!)/(n !)={1. 3. 5 (2n-1)}2^ndot

Prove that: ((2n)!)/(n !)={1. 3. 5 (2n-1)}2^ndot

Prove that: ((2n)!)/(n !)={1. 3. 5..... (2n-1)}2^ndot