A radioactive nucleus initially at rest decays by emitting an electron and neutron at right angle to one another. The momentum of neutron is `3.2xx10^(-24)kgm//s` and the momentum of neutron is `6.4xx10^(-24)kgm//sec` . The direction of the recoiling nucleus with that of the electron motion is:

A neutron initially at rest, decays into a proton, an electron and an antineutrino. The ejected electron has a momentum of 1.4xx10^-26 kg.m/s nd the antineutrino 6.4xx10^27 kgm/s. Find the recoil speed of the proton a. if the electron and the antineutrino are ejected along the same directioin and b. if they are ejected along perpendicular directions. Mass of the proton 1.67xx10^-27 kg.

A neutron initially at rest, decays into a proton, an electron and an antineutrino. The ejected electron has a momentum of 1.4xx10^-26 kg-m/s and that of antineutrino 6.4xx10^-27 kg-m/s. Find the recoil speed of the proton a. if the electron and the antineutrino are ejected along the same direction and b. if they are ejected along perpendicular directions. Mass of the proton 1.67xx10^-27 kg.

A neutron initially at rest, decays into a proton, an electron and an antineutrino. The ejected electron has a momentum of 1.4xx10^-26 kg-m/s and that of antineutrino 6.4xx10^-27 kg-m/s. Find the recoil speed of the proton a. if the electron and the antineutrino are ejected along the same direction and b. if they are ejected along perpendicular directions. Mass of the proton 1.67xx10^-27 kg.

The uncertainty in the momentum of an electron is 1.0xx10^(-5)kgms^(-1) . The uncertainty in position will be (h=6.6xx10^(-34)kgm^(2)s^(-1))

A neutron intially at rest, decays into a proton, an electron and an antineutrio. The ejected electron has a momentum of p_(1) = 1.4× 10^(-28) kg-m/s and the antineutrino p_(2) = 6.5 ×10^(–27) kg-m/s. Find the recoil speed of the proton if the electron and the antineutrino are ejected along the the same direection.

The uncertainity in momentum of an electron is 1 xx 10^(-5) kg.m//s . The uncertainity in its position will be (h = 6.62 xx 10^(-34)kg.m//s)