" he no.of solution of equation "sin5x cos3x=sin6x cos2x" in the interval "[

Find the number of solutions of the equation sin5x cos3x=sin6x cos2x,x in[0,pi]

No.of solution of equation : sin x=x^(2)+x+1

The number of solutions of the equation cos2x sin6x=cos3x sin5x in the interval [0,pi] is/are equal to 'a' (A) 'a' is prime number (B) y=|x-1|+|x-2|+....+|x-(a+4)| then y_(min)=20 (C) 'a' lies in the range of y=x^(2)+(1)/(x^(2)+1) (D) x^(3)=a+x^(2) has 3 real roots

Number of solutions of the equation sin 5x cdot cos 3x = sin 6x cdot cos 2x , In the interval [0, pi] is

The solution(s) of the equation cos2x sin6x=cos3x sin5x in the interval [0,pi] is/are pi/6 (b) pi/2 (c) (2pi)/3 (d) (5pi)/6

The number of solutions of the equation 16(sin^(5)x +cos^(5)x)=11(sin x + cos x) in the interval [0,2pi] is

The number of solutions of the equation 16(sin^(5)x +cos^(5)x)=11(sin x + cos x) in the interval [0,2pi] is

The number of solutions of the equation 16(sin^(5)x +cos^(5)x)=11(sin x + cos x) in the interval [0,2pi] is

The number of solutions of the equation 16(sin^(5)x +cos^(5)x)=11(sin x + cos x) in the interval [0,2pi] is

The number of solutions of the equation 16(sin^(5)x +cos^(5)x)=11(sin x + cos x) in the interval [0,2pi] is