The line L given by `x/5+y/b=1` passes through the point (13, 32). The line K is parallel to L and has the equation `x/c+y/3=1` Then the distance between L and K is (1) `sqrt(17)` (2) `(17)/(sqrt(15))` (3) `(23)/(sqrt(17))` (4) `(23)/(sqrt(15))`

The line L given by (x)/(5)+(y)/(b)=1 passes through the point (13,32). The line K is parallel to L and by has the equation (x)/(c)+(y)/(3)=1. Then the distance between L and K is (a) sqrt(17)quad (b) (17)/(sqrt(15)) (c) (23)/(sqrt(17)) (d) (23)/(sqrt(15))

The line given by (x)/(5)+(y)/(b)=1 passes through the point (13,32) the line K is parallel to L and has the equation (x)/(c)+(y)/(3)=1 then the distance between L and K is

The line L is given by 2x+by=7 , passes through (8, 3). The line K is parallel to L and has the equation cx -3y=c . Find the distance between L and K.

The line L_(1):(x)/(5)+(y)/(b)=1 passes through the point (13, 32) and is parallel to L_(2):(x)/(c)+(y)/(3)=1. Then, the distance between L_(1) andL_(2) is

The line L_(1):(x)/(5)+(y)/(b)=1 passes through the point (13, 32) and is parallel to L_(2):(x)/(c)+(y)/(3)=1. Then, the distance between L_(1) andL_(2) is

Let L be the line x-2y+3=0 .The equation of line L_1 is parallel to L and passing through (1,-2).Find the distance between L and L_1 .

The shortest distance between line y-x=1 and curve x=y^2 is (a) (3sqrt2)/8 (b) 8/(3sqrt2) (c) 4/sqrt3 (d) sqrt3/4

The distance between the parallel lnes y=2x+4 and 6x-3y-5 is (A) 1 (B) 17/sqrt(3) (C) 7sqrt(5)/15 (D) 3sqrt(5)/15

The distance between the parallel lnes y=2x+4 and 6x-3y-5 is (A) 1 (B) 17/sqrt(3) (C) 7sqrt(5)/15 (D) 3sqrt(5)/15

If the line (x+1)/(2) = (y+1)/(3) = (z+1)/(4) meets the plane x + 2y + 3z = 14 at P, then the distance between P and the origin is a) sqrt(14) b) sqrt(15) c) sqrt(13) d) sqrt(12)