xy(dy)/(dx)=(x+2)(y+2)

xy (dy)/(dx) =x^(2) +2y^(2)

y The differential equation of all circles passing through the origin and having their centres on the x-axis is (1)x^(2)=y^(2)+xy(dy)/(dx) (2) x^(2)=y^(2)+3xy(dy)/(dx)y^(2)=x^(2)+3xy(dy)/(dx)y^(2)=x^(2)-2xy(dy)/(dx)

(dy)/(dx)=(x^(2)-y^(2))/(xy)

Solve xy(dy)/(dx)=x^2+2y^2

Solve xy(dy)/(dx)=x^2+2y^2

(dy)/(dx)=xy+2y+x+2

xy (dy)/(dx) = x^(2) + 2y^(2) , y(1) = 0

Particular solution of the differential equation xy(dy)/(dx)=x^(2)+2y^(2),y(1)=0, is