Solve `[(2x+1)!]/[(x+2)!] xx [(x-1)!]/[(2x-1)!] =3/5` ; `(x in N)`

solve (2x+1)/(3x-2)=2/5

Solve: 3(x-1) - (x-2) = x + 2(x-1)

Express (2x+1)! in terms of (2x-1)!,(x+2)! in terms of (x-1)! .Hence, solve the equation ((2x+1)!)/((x+2)!)xx((x-1)!)/((2x-1)!)=3/5

Solve , 1/(x - 2) + 1/x = 8/(2x + 5)

Solve for x (1)/( 2x -3) + (1)/(x -5) =1," " x ne 3/2,5

Solve: (x^(2)-2x+5)/(3x^(2)-2x-5)>(1)/(2)

Solve (1)/(x-1)+(2)/(x-2)=(3)/(x-3)

Solve (2x-3)/(x-1)+1=(6x-x^(2)-6)/(x-1)

Solve: 3x+1/5=2-x

Solve: (3x+5)/(2x+1) =1/3 .