In the given figure,O is the centre of the circle `/_OAB=30^@` and `/_OCB=40^@`. Calculate `/_AOC`

O is the center of circle,/_ACB=40^(@) Find /_OAB

In the given figure,O is the centre of a circle,/_AOB=40^(@) and /_BDC=100^(@), find /_OBC.

In Figure,O is the centre of the circle.If /_APB=50^(@), find /_AOB and /_OAB

In figure, O is the centre of the circle angleBCO=30^(@) . Find X and Y.

In the figure, O is the centre of the circle. Prove /_AOC=/_AFC+/_AEC .

In the given figure, O is the centre of the circle. If angle BAO = 30^@ and angle BCO = 50^@ , then angle AOC is equal to: दिए गए आकृति में, O वृत्त का केंद्र है। यदि angle BAO = 30^@ और angle BCO = 50^@ , तो angle AOC का मान है :