If the system of linear equations x+ay+z...

If the system of linear equations `x+ay+z=3 and x+2y+2z=6 and x+5y+3z=b` has no solution, then (a) `a=-1,b=9 (2) a=-1,b != 9` (3) `a != -1 , b =9` (4) `a=1,b != 9`

Similar Questions

Explore conceptually related problems

The following system of linear equations 2x + 3y + 2z = 9 3x + 2y + 2z = 9 x - y + 4z = 8

The system of linear equations x+y-z=6,x+2y-3z=14 and 2x+5y-lambda z=9 has a unique solution (A) lambda=8( B )lambda!=8(C)lambda=7 (D) lambda!=7

If the system of equations x-2y+3z=9 2x+y+z=b x-7y+az=24 , has infinitely many solutions, then a - b is equal to ...........

For the system of equations: x+2y+3z=1 2x+y+3z=2 5x+5y+9z=4

The following system of linear equations has x+ 2y + 3z=1,2x + y + 3z = 2, 5x+ 5y + 9z = 4

The system of the linear equations x + y – z = 6, x + 2y – 3z = 14 and 2x + 5y – lambdaz = 9 (lambda in R) has a unique solution if

The system of linear equations x - 2y + z = 4 2x + 3y - 4z = 1 x - 9y + (2a + 3)z = 5a + 1 has infinitely many solution for: