Engine of a car can produce a maximum acceleration `2 m//s^(2)` and its brakes can produce a maximum retardation `3 m//s^(2)`. Minimum time in which the car can travel a distance 6 km is:

A scooter can produce a maximum acceleration of 5ms^(-2) .Its brakes can produce a maximum retardation of 10ms^(-2) .The minimum time in which it can cover a distance of 1.5 km is?

A scooter can produce a maximum acceleration of 5ms^(-2) .Its brakes can produce a maximum retardation of 10ms^(-2) .The minimum time in which it can cover a distance of 1.5 km is?

A scooter can produce a maximum acceleration of 5m s^(-2) . Its brakes can produce a maximum retardation of 10 "ms"^(-2) . The minimum time in which it can cover a distance of 1.5 km is ?

The engine of a motoecycle can produce a maximum acceleration of 5 m//s^(2) . Its brakes can produce a maximum retardation of 10 m//s^(2) . What is the minimum time in which the motorcycle can cover a distance of 1.5 km ?

The accelerator of a train can produce a uniform acceleration of 0.25ms^(-2) and its brake can produce a retardation of 0.5ms^(-2) The shortest time in which the train can travel between two stations 8 km apart is x minuts and 10 s, if it stops at both stations. The value of x is.

The maximum acceleration that can be produced by the engine of a vehicle is 5ms^(-2) and the maximum retardation is brake can produce is 10ms^(-2) . Then the minimum time during which it can cover a distance of 60 m is

The driver of a car stops his car by applying brakes to produce a uniform retardation of 8 m//s^2 , the initial speed of the car is 72 kmph.Calculate the stopping distance of the car.