int(d theta)/(b cos theta+c sin theta)vec a=pi

int (sin theta + cos theta) * d theta

int_(0)^(2pi) (sin 2 theta)/(a-b cos 2 theta )d theta =

If : sin^(2) ((pi)/(4) + (theta)/(2)) - cos^(2) ((pi)/(4) + (theta)/(2))= A) sin theta B) cos theta C) sin 2 theta D) cos 2 theta

If int (sin 3 theta + sin theta ) cos theta e ^(sin theta ) d theta = (A sin ^(3) theta + B cos ^(2) theta + C sin theta + D cos theta +E)e^(sin theta)+F, then:

int (d theta)/((sin theta - 2 cos theta)(2 sin theta + cos theta))

int (d theta)/((sin theta - 2 cos theta)(2 sin theta + cos theta))

Integration using rigonometric identities : int(sin theta)/(cos3 theta)+(sin 3 theta)/(cos9 theta)+( sin9 theta)/(cos 27theta)d theta=...+c

int cos 2theta log ((cos theta+sin theta)/(cos theta-sin theta))d theta

int cos2 theta * ln ((cos theta + sin theta) / (cos theta-sin theta)) d theta

Evaluate: int cos2 theta ln((cos theta+sin theta)/(cos theta-sin theta))d theta