The compound sodium polymetaphosphate `(Na[Na_(4)(PO_(3))_(6)])` is called calgon because

632 g of sodium thiosulphate (a_(2)S_(2)O_(3)) reacts with copper sulphate to form cuproc thiosulphate which is reduced by sodium thiosulphate to give cuprous compound which is dissolved in excess of sodium thiosulphate to form a complex compound sodium cuprothisosulphate (Na_(4)[Cu_(6)(S_(2)O_(3))_(5)]) , (MW=1033) CuSO_(4) + Na_(2)S_(2)O_(3) rarr CuS_(2)O_(3) + Na_(2)SO_(4)" " [very fast] 2CuSO_(4)+Na_(2)S_(2)O_(3)+Na_(2)S_(2)O_(3) rarr Cu_(2)S_(2)O_(3) + Na_(2)S_(4)O_(6) 3Cu_(2)S_(2)O_(3) + 2Na_(2)S_(2)O_(3) rarr Na_(4)[Cu_(6)(S_(2)O_(3))_(5)] " " (Sodium cuprothisoulphate ) In this process , 0.2 mole of sodium cuprothiosulphate is formed .(O=16 , Na=23 , S=32) It instead of given amount of sodium thiosulphate, 2 moles of sodium thiosulphate along with 3 moles of CuSO_(4) were taken initially . Then, moles of sodiu cuprothiosulphate formed is:

632 g of sodium thiosulphate (a_(2)S_(2)O_(3)) reacts with copper sulphate to form cuproc thiosulphate which is reduced by sodium thiosulphate to give cuprous compound which is dissolved in excess of sodium thiosulphate to form a complex compound sodium cuprothisosulphate (Na_(4)[Cu_(6)(S_(2)O_(3))_(5)]) , (MW=1033) CuSO_(4) + Na_(2)S_(2)O_(3) rarr CuS_(2)O_(3) + Na_(2)SO_(4)" " [very fast] 2CuSO_(4)+Na_(2)S_(2)O_(3)+Na_(2)S_(2)O_(3) rarr Cu_(2)S_(2)O_(3) + Na_(2)S_(4)O_(6) 3Cu_(2)S_(2)O_(3) + 2Na_(2)S_(2)O_(3) rarr Na_(4)[Cu_(6)(S_(2)O_(3))_(5)] " " (Sodium cuprothisoulphate ) In this process , 0.2 mole of sodium cuprothiosulphate is formed .(O=16 , Na=23 , S=32) Moles of sodium thiosulophate reacted and unreacted after the reaction are respectively,

632 g of sodium thiosulphate (a_(2)S_(2)O_(3)) reacts with copper sulphate to form cuproc thiosulphate which is reduced by sodium thiosulphate to give cuprous compound which is dissolved in excess of sodium thiosulphate to form a complex compound sodium cuprothisosulphate (Na_(4)[Cu_(6)(S_(2)O_(3))_(5)]) , (MW=1033) CuSO_(4) + Na_(2)S_(2)O_(3) rarr CuS_(2)O_(3) + Na_(2)SO_(4)" " [very fast] 2CuSO_(4)+Na_(2)S_(2)O_(3)+Na_(2)S_(2)O_(3) rarr Cu_(2)S_(2)O_(3) + Na_(2)S_(4)O_(6) 3Cu_(2)S_(2)O_(3) + 2Na_(2)S_(2)O_(3) rarr Na_(4)[Cu_(6)(S_(2)O_(3))_(5)] " " (Sodium cuprothisoulphate ) In this process , 0.2 mole of sodium cuprothiosulphate is formed .(O=16 , Na=23 , S=32) Moles of sodium thiosulophate reacted and unreacted after the reaction are respectively,

Calgon is Na_2[Na_4(PO_4)_3)] ,

A branded tooth paste contains 0.754 g sodium in form of sodium monofluoroortho phosphate (Na_(3)PO_(4)F) in 100 mL solution. Calculate the amount of Na_(3)PO_(4)F present in 100 mL of solution.