Home
Class 10
MATHS
Find the value of k, for which 2k+7, 6k-...

Find the value of k, for which 2k+7, 6k-2 and 8k+4 are 3 consecutive terms of an AP.

Text Solution

Verified by Experts

`T_(n+1)-T_n=T_n=T_(n-1)`
`8k+4-6k+2=6k-2-2k-7`
`2k+6=4k-9`
`k=15/2`.
Promotional Banner

Similar Questions

Explore conceptually related problems

For what value of k will k + 9, 2k - 1 and 2k + 7 are the consecutive terms of an A.P.?

Q. For what value of k will k+9, 2k-1 and 2k+7 are the consecutive terms of an A.P.

Q.For what value of k will k+9,2k-1 and 2k+7 are the consecutive terms of an A.P.

Find the value of 'k' , so that k+2, 4k-6 and 3k-2 are the three consective terms of an A.P.

For what value of k will k + 9, 2k - 1, 2k + 7 be consecutive terms of a AP.

Determine k so that k+2, 4k-6 and 3k-2 are three consecutive terms of an AP.

Determine k so that k+2, 4k-6 and 3k-2 are three consecutive terms of an A.P.

If k ,\ 2k-1 and 2k+1 are three consecutive terms of an A.P., the value of k is

If k ,\ 2k-1 and 2k+1 are three consecutive terms of an A.P., the value of k is