How much energy will be necessary for making a body of 500 kg escape from the earth
`[g=9.8 ms^(2)," radius of earth "=6.4xx10^(6)m]`

How much energy will be needed for a body of mass 100kg to escape from the earth- (g = 10m//S^(2) and radius of earth = 6.4 xx 10^(6) m)

How much energy will be needed for a body of mass 100kg to escape from the earth- (G = 10M//S^(2) and radius of earth = 6.4 xx 10^(6) m)

How much energy would be needed for a body of mass 10 kg to escape from the earth ? Take g= 10 m*s^(-2) and R_e=6400 km.

If a spaceship orbits the earth at a height of 500 km from its surface, then determine its (i) kinetic energy, (ii) potential energy, and (iii) total energy (iv) binding energy. Mass of the satellite = 300 kg, Mass of the earth = 6xx10^(24) kg , radius of the earth = 6.4 xx 10^(6) m, G=6.67 xx 10^(-11) "N-m"^(2) kg^(-2) . Will your answer alter if the earth were to shrink suddenly to half its size ?

If a spaceship orbits the earth at a height of 500 km from its surface, then determine its (i) kinetic energy, (ii) potential energy, and (iii) total energy (iv) binding energy. Mass of the satellite = 300 kg, Mass of the earth = 6xx10^(24) kg , radius of the earth = 6.4 xx 10^(6) m, G=6.67 xx 10^(-11) "N-m"^(2) kg^(-2) . Will your answer alter if the earth were to shrink suddenly to half its size ?

Find the escape velocity of a body from the surface of the earth. Given radius of earth = 6.38 xx 10^(6) m .

What is the force of gravity on a body of mass 150 kg lying on earth (Mass of earth =6 xx 10^(24) kg Radius of earth = 6 .4 xx 10^(6) m G= 6 .7 xx 10-11 Nm^2//kg^2)

A satellite orbits the earth at a height of 3.6xx10^(6)m from its surface. Compute it’s a kinetic energy, b. potential energy, c. total energy. Mass of the satellite =500kg mass of the earth =6xx10^(24) kg, radius of the earth =6.4xx10^(6), G=6.67xx10^(-11)Nm^(2)kg^(-2) .

A satellite orbits the earth at a height of 3.6xx10^(6)m from its surface. Compute it’s a kinetic energy, b. potential energy, c. total energy. Mass of the satellite =500kg mass of the earth =6xx10^(24) kg, radius of the earth =6.4xx10^(6), G=6.67xx10^(-11)Nm^(2)kg^(-2) .

What is the value of g at a height 8848 m above sea level. Given g on the surface of the earth is 9.8 ms^(-2) . Mean radius of the earth = 6.37 xx 10^(6) m .