The rate constant for the decomposition of hydrocarbons is `2.418 × 10^(–5)s^(– 1)` at 546 K. If the energy of activation is `179.9 kJ//mol`, what will be the value of pre-exponential factor.

The rate constant for the decomposition of hydrocarbons is 2.418 xx 10^(-5)s^(-1) at 546 K. If the energy of activation is 179.9 kJ/mol, what will be the value of pre-exponential factor.

The rate constant for the decomposition of hydrocarbons is 2.418xx10^(-5)s^(-1) as 546 K . If the energy of activation is 179.9 kJ.mol , what will be the value of pre-exponential factor ?

The rate constant for the decomposition of hydrocarbons is 2.418 xx10^(-5)s^(-1) at 546 K. If the energy of activatin is 179.9 kJ//mol. What will be the value of per-exponential factor ?

The rate constant for the decomposition of hydrocarbons is 2.418 xx 10^(-5) "s"^(-1) at 546 K. If the energy of activation is 179.9" kJ mol"^(-1) , what will be the value of pre-exponential factor?

The rate constant for the decomposition of hydrocarbons is 2.418xx10^(-5)s^(-1) at 546K . If the energy of activation is 179.9kJ mol^(-1) , what will be the value of pre - exponential factor?