Home
Class 12
PHYSICS
Under an adiabatic process, the volume o...

Under an adiabatic process, the volume of an ideal gas gets doubled. Consequently the mean collision time between the gas molecule changes from `tau_(1)` to `tau_(2)` . If `(C_(p))/(C_(v))=gamma` for this gas then a good estimate for `(tau_(2))/(tau_(1))` is given by :

Promotional Banner

Similar Questions

Explore conceptually related problems

One mole of ideal gas goes through process P = (2V^2)/(1+V^2) . Then change in temperature of gas when volume changes from V = 1m^2 to 2m^2 is :

One mole of ideal gas goes through process P = (2V^2)/(1+V^2) . Then change in temperature of gas when volume changes from V = 1m^2 to 2m^2 is :

During an adiabatic process , the pressure p of a fixed mass of an ideal gas change by Deltap and its volume V change by DeltaV . If gamma=C_(p)//C_(v) then DeltaV//V is given by

The temperature of an ideal gas undergoing adiabatic expansion varies with volume as T prop V^(-(3)/(4)) , then the value of (C_(P))/(C_(V)) for the gas is

The temperature of an ideal gas undergoing adiabatic expansion varies with volume as T prop V^(-(3)/(4)) , then the value of (C_(P))/(C_(V)) for the gas is

Which graph correctly represents the variation between relaxation time (tau) of gas molecules with absolute temperature (T) of the gas?