1 g of a monobasic acid dissolved in 200 g of water lowers the freezing point by `0.186^@ C`.On the other hand when 1 g of the same acid is dissolved in water so as to make the solution 200 mL , this solution requires 125 mL of 0.1 N NaOH for complete neutralization. If `alpha` for the acid is `x xx10`.
Find x:

1g of a monobasic acid dissolved in 200g of water lowers the freezing point by 0.186^(@)C . On the other hand when 1g of the same acid is dissolved in water so as to make the solution 200mL , this solution requires 125mL of 0.1 N NaOH for complete neutralization. Calculate % dissociation of acid ? (K_(f)=1.86(K-kg)/("mol"))

0.126 g of acid required 20 mL of 0.1 N NaOH for complete neutralisation. The equivalent mass of an acid is

0.126 g of acid required 20 mL of 0.1 N NaOH for complete neutralisation. The equivalent mass of an acid is

7.5 g of an acid are dissolved per litre of the solution. 20 mL of this acid solution required 25 mL of N//15 NaOH solution for complete neutralization. Calculate the equivalent mass of the acid.