Consider a series L-R circuit in which `L=(1)/(pi)H` and resistance `R = 100 Omega ` . When the circuit is connected to a.c. source 220 V, 50 H. Find the current drawn from the source.

In an ac circuit , L = (0.4)/(pi) H and R = 30 Omega . If the circuit has an alternating emf of 220 V, 50 cps, the impedance and the current in the circuit will be :

A resistance of 160 Omega is used in series with an inductance L and an a.c. of 230 V, 50 Hz. If the current in the circuit is 0.25A, find L.

A series L-C-R circuit with a resistance of 500 Omega is connected to an a.c. source of 250 V. When only the capacitance is removed, the current lags behind the voltage by 60^(@) . When only the inductance is removed, the current leads the voltage by 60^(@) . What is the impedance of the circuit?

An LCR series circuit with L =0.5H, C=10xx10^(-6) F, R=100 Omega is connected to an A.C. source of frequency of 50 Hz. The impedance of the circuit is …….

In LCR circuit, inductance L = 2/pi H , capacitance C = 10/pi F and resistance 10 Omega are connected in series to A.C. source of frequency = 50 Hz. Find:-impedance of the circuit.

In LCR circuit, inductance L = 2/pi H , capacitance C = 10/pi F and resistance 10 Omega are connected in series to A.C. source of frequency = 50 Hz. Find:-inductive reactance

In a series L, R, C, circuit which is connected to a.c. source. When resonance is obtained then net impedance Z will be

In a series L, R, C, circuit which is connected to a.c. source. When resonance is obtained then net impedance Z will be

An LCR series circuit with L = 100 mH, C = 100 µF.R = 120 Ω is connected to an aC source of emf = (30 V) sin (100 S^(-1)) L Find the impedance and resonant frequency of the circuit.